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How Homework is done in the ICL Household

An on-line chat between Batgirl and ICL:

7:34 PM Séana: I know how to do g (1) = 3 - 2 x, but the "2" is something new that I don't know how to deal with. I've tried dividing both sides by two only to find that the final result did not conincide with the answer sheet.
7:35 PM me: What does it say to do at the top of the question?
7:37 PM Séana: "For g (x) = 3 - 2 x, find: (a) g(3) (b) g(0) (c) g(-2) ...
7:38 PM me: Ok so show me one you know how to do
7:40 PM Séana: g (3) = 3 - 2 x ... g (3) = 3 - 2 (3) ... g (3) = 3 - 6 ... g (3) = - 3
g (3) being the y-coordinate, and -3 being the x-coordinate
sorry
7:41 PM not "-3"
just "3"
me: I think it is -3
Séana: the same "3" present in the g (3)
I mean not the answer, but the x-coordinate
7:42 PM me: o
so what' s the ? you can't do again?
Séana: 2 g (1) = 3 - 2 x
the two at the beginning
me: divide both 3 and 2x by 2
Séana: I tried dividing both sides by two to no avail
7:43 PM me: g(1)=3/2 - 2x/2
Séana: ok
7:45 PM me: so what' s the answer already!!!!
Séana: so... g (1) = 3/2 - 2x/2 ... g (1) = 3/2 - [2 (1)]/2 ... g (1) = 3/2 - 2/2 ... g (1) = 1.5 - 1 ... g (1) = 0.5
7:46 PM me: es
yes
Séana: which is wrong according to my answer sheet
7:47 PM me: what does it say? 1/2
?
Séana: 2
7:48 PM me: 2g(1)=3-2x
2g(1)-3-2(1)
2g(1)=3-2(1) I meant
2g(1)=3-2
2g(1)=1
7:49 PM g(1)=1/2
I think the answer sheet is wrong
ask your teacher
are you sure you wrote down the ? right?
Séana: yep
7:53 PM thanks anyways

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